2. $6000 is divided between two accounts, one paying 4% interest and the other paying 5% interest. At the end of one interest period, the interest earned by the 4% account exceeds the interest earned by the 3% account by $65. How much was invested in each account?

Answer:The correct answer is: - Account “A”: $3500 - Account “B”: $2500 Step-by-step explanation:* As the main account is split in two: - Account “A”: n - Account “B”: $6000-n * Let’s consider Account “A” will be applied 4% interest and Account “B” will be applied 3% interest. * In the problem, the Simple Interest Rate is used: Simple Interest Formula = Principal x Interest Rate x Time Period * According to the problem, at the end of 1 interest period, applying the Simple Interest Formula: - Account “A”: 4n/100 - Account “B”: (3($6000-n))/100 + $65 - Solving the equation: 4n/100=   3($6000-n)/100  + $65  4n/100=$18000/100-  3n/100+$65 7n/100=$180+$65  7n=$245 x 100 n=$3500 → Account “A”: $3500 → Account “B”: $6000-$3500 = $2500