What is the decibel level of the sound of a monster truck with intensity 10−2 watts per square inch? Use a logarithmic model to solve.

Answer:BdB = 68.10 decibelsStep-by-step explanation:BdB = 10 log10 I / Io where BdB is the sound intensity level in decibels, I is the sound intensity on the linear scale (W / m²) and I0 is the hearing threshold (10^-12 W / m²). Converting Io de 10^-12 W/m² to W/in², tenemos 10^-12 W/m² = 1.5500031000062x10^-9 W/in² So, applying the equation or formula, BdB = 10 log10 (10 ^ -2 W/in² / 1.5500031000062x10^-9 W/in² )BdB = 10 log10 (0.64516x10^6) BdB = 10 log10 (6,451,600) Being log10 (6,451,600) = 6.8096674332398761189214526331036, then BdB = 10 x 6.8096674332398761189214526331036 BdB = 68.096674332398761189214526331036 BdB = 68.10 decibels